Feeling lucky? How many correct numbers must you choose in order to win? That is, a given number, say 10, can only appear ONCE in the winning. • Observe and analyse the history results, you can make wild guess by looking at the interval winning times. The smaller gap the better. • History will repeat itself, most probably will. So buy your lucky numbers at your favourite outlets when you see the repeating pattern. • Hit more winning chances by buying the numbers using pau/iperm/mbox methods. Pau/iperm/mbox are the few terms that indicate the permutation of the numbers. Bondan prakoso mp3. For example 1234, when you pau/iperm/mbox you'll get 1324, 1342, 3142 and so on. Which is total of 24 numbers. • Buy with confident, of course at your own will. If you lose, it's not end of your life;). Life is short, so have fun. Four Digits Magic Prediction Number 1089 invariably comes up as a result of a 2-step procedure applies to a 3-digit number. This fact serves as the basis for a baffling mathematical prediction. It is even more interesting to apply the same procedure to a 4-digit number. The result is not unique; there are 4 possibilities. However, just glancing at the original number I can tell you the result of the procedure. Bovis infection? Bovis commonly are seen in calves weighing 300 to 600 pounds (lb.), but also are found in heavier cattle. Bovis quickly can become a pen problem, look for these telltale signs that M. These symptoms often appear three to four weeks after arrival, especially after commingling, crowding, and wet and cold weather. Bovine viral diarrhea merck veterinary manual. Symptoms of disease associated with M. There are simple rules, not hard to remember; the rules underlie a spectacular mathematical trick. I am going to show how this works. The procedure is this: For any integer A, let A' be obtained by writing A backwards. Compute B =|A - A'| and C = B + B'. Before reading further you may want to investigate the possible outcomes. The applet below is a calculator designed specifically for that purpose. The blue numbers are clickable. The digits increase if clicked to the right of their vertical axis, and decrease if clicked to the left of the axis. (Note: The difference B =|A - A'| may come out with fewer than 4 digits. When this happens B is padded with the necessary number of zeros to produce a 4-digit string which then is written backwards to give B'. For example, if B = 87, B' = 7800 because the padded B is a string 0087.) If you are reading this, your browser is not set to run Java applets. Try IE11 or Safari and declare the site as trusted in the Java setup. For 4-digit numbers, the algorithm may lead to one of 990, 9999, 10890, 10899. A 4-digit decimal number A could be written as A = 1000a + 100b + 10c + d, giving A' = 1000d + 100c + 10b + a. Assume that a ≥ d. (If that is not true just swap A and A'.) We first consider the case where a and d are different: a > d. Then B = 1000(a - d) + 100(b - c) + 10(c - b) + (d - a). The key case here is when b = c so that B = 1000(a - d) + (d - a). Since d - a is negative we have to borrow from the first term: B = 1000(a - d - 1) + 990 + (10 + d - a). Introduce x = a - d - 1 and y = 10 + d - a. Then B = x99y and B' = y99x, with x + y = 9, making B + B ' = 1000(x + y) + 990 + 990 + (x + y) = 9000 + 1980 + 9 = 10989. Next, assume c > b. In this case, B = 1000(a - d - 1) + 100(10 + b - c) + 10(c - b - 1) + (10 + d - a) and B' = 1000(10 + d - a) + 100(c - b - 1) + 10(10 + b - c) + (a - d - 1), so that B + B' = 9999. If b > c, we proceed differently: B = 1000(a - d) + 100(b - c) + 10(c - b) + (d - a) = 1000(a - d) + 100(b - c - 1) + 10(9 + c - b) + (10 + d - a). Which gives B' = 1000(10 + d - a) + 100(9 + c - b) + 10(b - c - 1) + (a - d) so that B + B' = 100010 + 1008 + 108 + 10 = 10890. How we obtain the last possible outcome? There is only one case remaining: a = d. ` ` Please visit this website: >>. Origo 1500 gimbal. If b = c, the number is palindromic and the result is 0. Otherwise, A and A' have the same thousand and unit digits, so that necessarily B is a 3-digit number ending in 0: xy0, with x + y = 9. Since, at this stage, we are dealing with 4-digit number, it needs to be padded to produce B' = yx0 (xy0 → 0xy0 → 0yx0 → yx0), giving B + B' = 990. It looks like 4-digit numbers allow for a presentation of spectacular mental math. ![]() Ask your audience to produce a 4-digit number. If a = d, the result is either 0 or 990. ![]() If need be, read it backwards to have a > d. Then b > c gives 10890, b = c leads to 10899, and b d, b = c), 10UV0 (a > d, b > c), VVVV (a > d, b.
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